(3a^2+1)-(4+2a^2)=0

Solution for (3a^2+1)-(4+2a^2)=0 equation:

Simplifying
(3a2 + 1) + -1(4 + 2a2) = 0

Reorder the terms:
(1 + 3a2) + -1(4 + 2a2) = 0

Remove parenthesis around (1 + 3a2)
1 + 3a2 + -1(4 + 2a2) = 0
1 + 3a2 + (4 * -1 + 2a2 * -1) = 0
1 + 3a2 + (-4 + -2a2) = 0

Reorder the terms:
1 + -4 + 3a2 + -2a2 = 0

Combine like terms: 1 + -4 = -3
-3 + 3a2 + -2a2 = 0

Combine like terms: 3a2 + -2a2 = 1a2
-3 + 1a2 = 0

Solving
-3 + 1a2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 1a2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 1a2 = 0 + 3
1a2 = 0 + 3

Combine like terms: 0 + 3 = 3
1a2 = 3

Divide each side by '1'.
a2 = 3

Simplifying
a2 = 3

Take the square root of each side:
a = {-1.732050808, 1.732050808}